Here is my code:
def missing_ch(number, string):
for i in range(len(string)):
if i==number:
continue
else:
print(string[i], end=' ')
return
string='hello'
num=int(input("enter the position of char"))
missing_ch(num, string)
How to get output characters printed in same line?
I see 3 issues in your program -
In the for
loop in second line , you have missed closing a bracket - for i in range (len(str):
, it should be - for i in range (len(str)):
There is no casting
in python, to convert input to string, you have use int
function, as int(...)
, so your line (int)(input(...))
should be - int(input(...))
.
In your for loop, you are defining the index as i
, but you are using ch
inside the loop, you should be using i
instead of `ch.
Example -
for i in range (len(str):
if(i==num):
continue
print(str[i],end=' ')
return
The print statement to print items without appending the newline is fine, it should be working.
A working example -
>>> def foo():
... print("Hello",end=" ")
... print("Middle",end=" ")
... print("Bye")
...
>>> foo()
Hello Middle Bye
To print on one line, you could append each letter on a string.
def missing_ch(num, str):
result = ""
for i in range (len(str)):
if (i == num):
continue
result+=str[i]
print result
string = 'hello'
num = (int)(input('enter the position of char'))
missing_ch(num, string)
#>helo
I'm new into python and my friend is giving me tasks to perform and one of them was to print a square made out of "*" and this is how I did it:
br = int(input("Enter a number: "))
for i in range(0, br):
print("*" * br)
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