using struct array as parameter in c++

Question

I'm having trouble while building this:

#include <stdio.h>
#include <conio.h>
#define N 3

struct cliente
{
    char nocliente[12];
    int edad;
    int precio;        
};

void imprimir(cliente *cliente1[N]);

int main()
{
    struct cliente cliente1[N];
    for(int i=0; i<N; i++)
    {
        printf("\nIngrese el nombre del cliente %d\n", i+1);
        scanf("%s", &cliente1[i].nocliente);
        printf("\nIngrese la edad del cliente %d\n", i+1);
        scanf("%d", &cliente1[i].edad);
        printf("\nIngrese el precio del articulo del cliente %d\n",  i+1);
        scanf("%d\n", &cliente1[i].precio);
    }

    imprimir(&cliente1[N]);

    getch();
    return 0;
}

void imprimir(cliente *cliente1[N])
{
    for(int i=0; i<N; i++)
    { 
        printf("%s", cliente1[i]->nocliente);
        printf("\n%d", cliente1[i]->edad);
        printf("\n%d", cliente1[i]->precio);
    }
}

This is the error the compiler outputs:

cannot convert `cliente*` to `cliente**` for argument `1` to `void imprimir(cliente**)`

I´ve tried declaring (cliente *cliente[]) in the parameters of the prototype and definition but the function but it doesn't work either

Answer 1

Use the following instead :

void imprimir(cliente *cliente1)

for your function declaration.

Answer 2

Make changes to ...

imprimir(&cliente1);//you are passing the whole thing not just #3


void imprimir(cliente *cliente1) //drop the N

Answer 3

• The correct (and confusing) syntax is

  void imprimir(/* const */ cliente (&cliente1)[N]);

  and then call it

  imprimir(cliente1);

• A simpler syntax:

   void imprimir(/* const */ cliente *cliente1, std::size_t size);

  with a call

  imprimir(cliente1, N);

• using class may help as std::vector or std::array

   std::array<cliente, N> cliente1; imprimir(/* const */ std::array<cliente, N>& cliente1);

  And call it

  imprimir(cliente1);

Note: I added const in comment as the array is not modified.