Exclude a pattern from grep result

Question

I use below command to search for a specific text in a directory and its sub-directories.

find . -exec grep -i -n -w 'search text' /dev/null {} \\;

Result is displayed in below format ./directory/filename:<line_number>:<matching text>

I want to exclude all lines with /* from the result.

How to do this?

OS Version: Sun OS 5.10

Answer 1

You could pipe the result through grep again, filtering out matches of /* :

find . -exec grep -i -n -w 'search text' /dev/null {} \; | grep -v '/\*'

where grep -v returns lines that don't match (and I'm assuming you mean a literal /* hence the regex).

Answer 2

通过grep -v'排除模式'传递整个内容