I want to change the entire page's content using javacript or jquery and display the 404 html page returned by ajax request. Is that possible? How?
Can use load() which is simplest of the $.ajax
shorthand methods
if( someCondition ){
$('body').load('404.html');
}
This may or may not be what you are looking for as intent is not entirely clear in the question
Using DOMParser to replace the contents of the documentElement with the documentElement from the HTML source in xhr.responseText
var dom = (new DOMParser).parseFromString(xhr.responseText, 'text/html');
// any attribute setting on `document.documentElement` etc here, then
document.documentElement.innerHTML = dom.documentElement.innerHTML;
dom = null;
Browser support of parsing HTML with DOMParser is
Google Chrome 30 +
Firefox 12 +
Internet Explorer 10 +
Opera 17 +
Safari 7.1 +
If you need to support legacy browsers consider instead of parsing, searching from the end for </html>
and the start of the String for <html
, finding the close >
and then extracting everything between these two, which then gets set as the innerHTML
The technical post webpages of this site follow the CC BY-SA 4.0 protocol. If you need to reprint, please indicate the site URL or the original address.Any question please contact:yoyou2525@163.com.