Compare arrays of different sizes and dimensions

Question

So here's the proposed problem.

Compare two arrays and return a new array with any items not found in both of the original arrays.

Here's what I have so far.

function diff(arr1, arr2) {
    for (var a in arr1) {
        for (var b in arr2) {
            if (arr1[a] == arr2[b]){
                arr2.splice(b,1);
            }
        }
    }
    return arr2;
}

diff([1, 2, 3, 5], [1, 2, 3, 4, 5]);

This code basically just compares each value of the first array with the second one. If a match is found it then removes the item using the splice function.

This works great for arrays that are one dimensional but how can I get it to work for multidimensional arrays such as:

diff([1, 2, 3, 5], [1, [2, 3], [4, 5]]);

What if these arrays are not just two dimensions but any number of dimensions. I should be able to iterate through every element of every array no matter they are set up.

Answer 1

With lodash you can do this :

 var a = [1, 2, 3, 5, 7], b = [1, [2, 3], [4, 5, [7]]]; var result = _.filter(_.flattenDeep(b), function(item){ return a.indexOf(item) === -1; }); console.log(result); $("body").append(JSON.stringify(result))

 <script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script> <script src="https://cdnjs.cloudflare.com/ajax/libs/lodash.js/3.10.0/lodash.min.js"></script> <body></body>

Compare arrays of different sizes and dimensions

Question

1 answers

solution1
0 2015-07-23 16:24:00

Compare arrays of different sizes and dimensions

Question

1 answers

solution1 0 2015-07-23 16:24:00

solution1
0 2015-07-23 16:24:00