Display data from one table when a column value in first table matches column value in second table

Question

I am having a really hard time with this one. I have two different tables namely "departure" and "editor data". I want to display data from departure when the data in "Name" column of departure matches the data in the "ven" column of editor_data.

i've tried the SQL query below, but it doesn't work properly.

 <?php

 SELECT Time, Location, Name FROM departure JOIN editor_data 
 ON departure.Name = editor_data.ven 

  ?>

eg

departure table can have either mike or rite in the "Name" field. So, if the "editor_data" has the value "mike" in the "ven" column then it should only display data related to "mike" and exclude rite's data.

Answer 1

Select only those records of departure table where name exists in editor_data.ven column

SELECT Time, Location, Name FROM departure where name in (SELECT ven from editor_data); 

Your issue arises because you try to join two tables based on the column name values which is not a PRIMARY KEY. Hence, the join condition fails and it results in a cross join, which returns the cartesian product combination of all records present. Hence, the issue can be avoided by calling a subquery on a selected (limited) list of values.

Answer 2

这就是我的工作方式

"SELECT Time, Location, Name FROM departure where Name LIKE (SELECT ven from editor_data where tour_id = '$id');"