Batch Change dir and use current dir as command

Question

i try to write a CMD to run a script written by me.

Script syntax is:

luajit.exe loader.lua nyufxlua "workingpath" suffix

workingpath and location of library are different.

I tried following:

@echo off

IF "%1%" == "" (
    GOTO :NOFILE
) ELSE (
    GOTO :FILE
)

:NOFILE
ECHO NO FILE GIVEN!
GOTO :EXIT

:FILE
SET "P=%CD%"
PUSHD C:\Projects\FXSpindle\trunk\deps\script\bin
luajit.exe loader.lua nyufxlua "%P%" %1%

:EXIT

I switch direcotry, run my file, but paramether "workingdir" is not correct. workingdir should be the path i runned this scirpt from (script is stored in System32 of my Windows)

As "workingdir" is always C:\\Projects\\FXSpindle\\trunk\\deps\\script\\bin given, but not the path i have opened my command line...

How to solve this problem?

Answer 1

i have the problem solved. I havent realized that i have to use POPD after PUSHD - so i was in wrong directory...

The correct code is:

@echo off

IF "%1%" == "" (
    GOTO :NOFILE
) ELSE (
    GOTO :FILE
)

:NOFILE
ECHO NO FILE GIVEN!
GOTO :EXIT

:FILE
SET "P=%CD%"
POPD C:\Projects\FXSpindle\trunk\deps\script\bin
luajit.exe loader.lua nyufxlua "%P%" %1%

:EXIT

Answer 2

使用%1来访问第一个参数，而不能在结尾加上％