I have aa form which let's the user select what they want to display. Now the results of this looks like that: 9, 10, 11
. These are IDs from the table.
These are the IDs of the type they what to show. I have my query already, but I want to add this part at the end of my query.
So in this case:
$query = "type_ID = $result1 or type_ID = $result2 or type_ID = $result3"
if printed out with echo:
type_ID = 9 or type_ID = 10 or type_ID = 11
How can I achieve this?
I tried to loop and it,however this did not work and I am confused how to do add the MySQL code to this.
$result = $result . $_GET['type_ID'][$i]
I'm a tad unsure of what it is you are trying to achieve but from what I understand this should do it:
<?php
$tID = $_GET['type_ID'];
$query = 'SELECT * FROM table WHERE';
$i = 0;
foreach($tID AS $id){
if($i == 0){
$query .= ' type_ID = ' . $id;
$i++;
}else{
$query .= ' OR type_ID = ' . $id;
}
}
Although if you are only looking for the type_ID I'd still recommend using IN()
like so:
<?php
$tID = $_GET['type_ID'];
$query = "SELECT * FROM table WHERE type_ID IN (" . implode(',',$tID) . ")";
In works just like OR, just instead of having to write multiple OR
you can just use a single IN()
:)
你试过这个吗?
$sql = "SELECT * FROM table WHERE ".$query;
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