I want to match a keyword using preg_match in php. regular expression is working perfectly on www.regexr.com but not in my php code. can someone help. Thankyou.
<?php
$regexx="/[sS]+([\s\t\r]*[\.\~\`\!\@\#\$\%\^\&\*\(\)\-\_\+\=\[\]\{\}\;\:\"\'\\\|\,\.\<\>\/\?\d\w]*)+[hH]+([\s\t\r]*[\.\~\`\!\@\#\$\%\^\&\*\(\)\-\_\+\=\[\]\{\}\;\:\"\'\\\|\,\.\<\>\/\?\d\w]*)+[aA]*([\s\t\r]*[\.\~\`\!\@\#\$\%\^\&\*\(\)\-\_\+\=\[\]\{\}\;\:\"\'\\\|\,\.\<\>\/\?\d\w]*)+[rR]*([\s\t\r]*[\.\~\`\!\@\#\$\%\^\&\*\(\)\-\_\+\=\[\]\{\}\;\:\"\'\\\|\,\.\<\>\/\?\d\w]*)+[eE]*
/";
if (preg_match($regexx, "S-hare"))
{
echo 'succeeded';
}
else
{
echo 'failed';
}
?>
Based on your comment:
I want to match the word 'share' written in any format. for example.. any special character or space in between 'share' would be detected.
I would suggest to simply remove every non alphabetics characters then match what is left.
var_dump($str = preg_replace("/[^a-z]/i", "", "sh@a/#~r: e !!!"));
var_dump($str === "share");
A raw single regex solution could be:
/[^az]*s[^az]*h[^az]*a[^az]*r[^az]*e[^az]*/i
Which is simple share and [^az]*
to match any non alphabetics series of characters between every letters.
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