File path problems in windows environment

Question

I have the following line of code:

"%s/ramp_adapter/user_%d/ramp_file_receipt/%d".format(new java.io.File(".").getAbsolutePath().replace("/.",""), endpointId, fileId)

If I print this line in window I get wrong file path:

E:\git\project\codeAdapters\rampAdapter\./ramp_adapter/user_1001/ramp_file_receipt/3

In unix, the file path is coming correct.

I know that I need to make it compatible with windows and so I tried using FilenameUtils but this didn't resolved the problem.

The path should be correct in all the environments.

Answer 1

Use File.getCanonicalFile() to norm the resulting string. It converts to the right separator and also removes . path segments.

String s = "E:\\git\\project\\codeAdapters\\rampAdapter\\./ramp_adapter/user_1001/ramp_file_receipt/3";
File f = new File(s).getCanonicalFile();
assertEquals("E:\\git\\project\\codeAdapters\\rampAdapter\\ramp_adapter\\user_1001\\ramp_file_receipt\\3", f.toString());

Answer 2

The current working directory . depends on how ie where the application was started. You might use

System.getProperty("user.dir")

instead of getting the absolute path.

It probably will exhibit the same problem: clicking under Windows will be problematic.

The solution/workaround might be to have a batch file under Windows.

I tend to use an application dependent directory in the user's home folder. When hidden with a preceding period:

File myAppDir = new File(System.getProperty("user.home") + "/.myappname";
myAppDir.mkdir();

Answer 3

1) Use System.getProperty("file.separator") to obtain the current OS file separator. 2) new java.io.File(".").getAbsolutePath() will return linux paths (/etc/uus/.)in Linux and Windows paths in windows (ex: C:\\xpto\\sdfs.)

You need to standardize as you wish.

Answer 4

Replace

"%s/ramp_adapter/user_%d/ramp_file_receipt/%d"

with

"%s" + File.separatorChar + "ramp_adapter" + File.separatorChar + "user_%d" + File.separatorChar + "ramp_file_receipt" + File.separatorChar + "%d"

Replace

getAbsolutePath().replace("/.","")

with

getAbsolutePath().replace(File.separator + ".", "")