I want to scrape this URL .
I am using phpQuery library for this purpose.
I want to scrape #weedmenuPane
from that link which contains some items and its prices.
Problem is, when I get scraped HTML, the required DIV is not in the scraped HTMl.
I have checked with Firebug but it is not coming from any AJAX call.
I thought it was coming by some kind of JS operation after HTML is loaded but I have also checked by disabling JS
in my browser, and that DIV is there, means not coming by any JS operation.
I want to know how it is coming and how it is being generated.
Here is code I have tried.
$html = file_get_contents($link, false, $context);
$html = phpQuery::newDocumentHTML($html);
echo pq("",$html);
echo pq("#weedmenuPane",$html)->html() . " here";
So, I have downloaded phpQuery and written a little test with your url.
This :
<?php
require 'phpQuery-onefile.php';
$url= "https://weedmaps.com/deliveries/green-door-west";
$HTML = file_get_contents($url);
$pq = phpQuery::newDocumentHTML($HTML);
$div = pq('#weedmenuPane', $pq);
echo $div; // Content of #weedmenuPane
// or with your code
echo pq("#weedmenuPane", $pq)->html() . " here";
?>
Return the content of the #weedmenuPane DIV.
So try to use this code or show me your code and we will find your problem.
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