curl command not executing via shell script in bash
Question
I'm learning shell scripting! for the same I've tried downloading the facebook page using curl on ubuntu terminal.
t.sh content
vi@vi-Dell-7537(Desktop) $ cat t.sh
curlCmd="curl \"https://www.facebook.com/vivekkumar27june88\""
echo $curlCmd
($curlCmd) > ~/Desktop/fb.html
Getting error when running the script as
vi@vi-Dell-7537(Desktop) $ ./t.sh
curl "https://www.facebook.com/vivekkumar27june88"
curl: (1) Protocol "https not supported or disabled in libcurl
But if the run the command directly then it is working fine.
vi@vi-Dell-7537(Desktop) $ curl "https://www.facebook.com/vivekkumar27june88"
<!DOCTYPE html>
<html lang="hi" id="facebook" class="no_js">
<head><meta chars.....
I will appreciate if anyone let me know the mistake I am doing in the script.
I've verified that curl library have ssl enabled.
4 answers
solution1
14 ACCPTED 2015-08-24 12:24:38
A command embedded within a parenthesis runs as a sub-shell so your environment variables will be missing.
Try eval:
curlCmd="curl 'https://www.facebook.com/vivekkumar27june88' > ~/Desktop/fb.html"
eval $curlCmd
solution2
3 2015-08-24 11:35:54
Create your script t.sh as this single line only:
curl -k "https://www.facebook.com/vivekkumar27june88" -o ~/Desktop/fb.html
As per man curl :
-k, --insecure
(SSL) This option explicitly allows curl to perform "insecure" SSL connections transfers.
All SSL connections are attempted to be made secure by using the CA certificate bundle
installed by default. This makes all connections considered "insecure" fail unless -k,
--insecure is used.
-o file
Store output in the given filename.
solution3
1 2015-08-24 18:52:42
As @Chepner said, go read BashFAQ #50: I'm trying to put a command in a variable, but the complex cases always fail! . To summarize, how you should do things like this depends on what your goal is.
If you don't need to store the command, don't ! Storing commands is difficult to get right, so if you don't need to, just skip that mess and execute it directly:
curl "https://www.facebook.com/vivekkumar27june88" > ~/Desktop/fb.htmlIf you want to hide the details of the command, or are going to use it a lot and don't want to write it out each time, use a function:
curlCmd() { curl "https://www.facebook.com/vivekkumar27june88" } curlCmd > ~/Desktop/fb.htmlIf you need to build the command piece-by-piece, use an array instead of a plain string variable:
curlCmd=(curl "https://www.facebook.com/vivekkumar27june88") for header in "${extraHeaders[@]}"; do curlCmd+=(-H "$header") # Add header options to the command done if [[ "$useSilentMode" = true ]]; then curlCmd+=(-s) fi "${curlCmd[@]}" > ~/Desktop/fb.html # This is the standard idiom to expand an arrayIf you want to print the command, the best way to do it is usually with
set -x:set -x curl " https://www.facebook.com/vivekkumar27june88 " > ~/Desktop/fb.html set +x
...but you can also do something similar with the array approach if you need to:
printf "%q " "${curlCmd[@]}" # Print the array, quoting as needed printf "\\n" "${curlCmd[@]}" > ~/Desktop/fb.html
solution4
0 2016-02-29 06:58:45
Install following softwares in ubuntu 14.04
- sudo apt-get install php5-curl
- sudo apt-get install curl
then run sudo service apache2 restart check your phpinfo() is enable with curl "cURL support: enabled"
Then check your command in shell script
RESULT= curl -L "http://sitename.com/dashboard/?show=api&action=queue_proc&key=$JOBID" 2>/dev/null
echo $RESULT
You will get response;
Thanks you.
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