I have a text file (one.txt) that contains an arbitrary number of key‐value pairs (where the key and value are separated by a colon – eg, x:17). Here are some (minus the numbers):
I need to open the file and create a dictionary that contains all of the key‐value pairs.
So far I have opened the file with
file = []
with open('one.txt', 'r') as _:
for line in _:
line = line.strip()
if line:
file.append(line)
I opened it this way to get rid of new line characters and the last black line in the text file. I am given a list of the key-value pairs within python.
I am not sure how to create a dictionary with the list key-value pairs. Everything I have tried gives me an error. Some say something along the lines of
ValueError: dictionary update sequence element #0 has length 1; 2 is required
Use str.split()
:
with open('one.txt') as f:
d = dict(l.strip().split(':') for l in f)
split()
will allow you to specify the separator :
to separate the key and value into separate strings. Then you can use them to populate a dictionary, for example: mydict
mydict = {}
with open('one.txt', 'r') as _:
for line in _:
line = line.strip()
if line:
key, value = line.split(':')
mydict[key] = value
print mydict
output:
{'mattis': 'turpis', 'lectus': 'per', 'tellus': 'nonummy', 'quam': 'ridiculus', 'Duis': 'ultricies', 'consequat': 'metus', 'nonummy': 'pretium', 'odio': 'mauris', 'urna': 'dolor', 'Aliquam': 'adipiscing'}
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