PHP/mySQL count($array[id]) = 1 even though there are 8 elemnts in the table

Question

Here's my code:

$host = "localhost";
$user = "root";
$pw = "";

$dbName = "mathgame";
$tblName = "fragen";
// mit mysql db verbinden

$con = mysqli_connect($host, $user, $pw, $dbName);
if ($con->connect_error) {
die ("Connection failed: " . $con->connect_error);}

// Datenanfrage an db

$result = mysqli_query($con, "select id from $tblName");
$array = mysqli_fetch_array($result);
echo count($array["id"]);

Comments are in German, but I think you get what the program does. So my problem is, that there are 8 "elements" in the fragen table. But when I count the array it returns one. What did I do wrong?

Answer 1

mysqli_fetch_array fetches a single row as an array, where each element is a column. You could use mysqli_num_rows to get the number of rows from the current query:

$result = mysqli_query($con, "select id from $tblName");
echo mysqli_num_rows($result);

Or, better yet, let the database do the heavy lifting for you:

$result = mysqli_query($con, "SELECT COUNT(*) FROM $tblName");
$array = mysqli_fetch_array($result);
echo $array[0];