How to convert this extensive Python loop to C++?

Question

I know very little on Python, but I'm quite experienced in C++. I was looking for an algorithm that would loop through the points in a hexagon pattern and found one written in Python that seems to be exactly what I need. The problem is that I have no idea how to interpret it.

Here is the Python code:

for x in [(n-abs(x-int(n/2))) for x in range(n)]:
    for y in range(n-x):
        print ' ',
    for y in range(x):
        print ' * ',
    print

I'd show you my attempts but there are like 30 different ones that all failed (which I'm sure are just my bad interpretation).

Answer 1

Hope this helps you.Tested both python and c++ code .Got same results.

#include <iostream>
#include <cmath> 

using namespace std;

int main() {
    // your code goes here
    int n = 10;
    int a[n];

    for(int j = 0; j < n; j++) {
       a[j] = n - abs(j - (n / 2)); 
    }

    for(int x = 0; x < n; x++) {
        for(int y = 0; y < (n - a[x]); y++) {
            std::cout << " " << std::endl;
        }
    }

    for(int k = 0; k < a[n-1]; k++) {
        std::cout << " * " << std::endl;
    }

    std::cout << "i" << std::endl;

    return 0;
}

Answer 2

auto out = ostream_iterator<const char*>(cout," ");

for(int i = 0; i != n; ++i) {
    auto width = n - abs(i - n/2);
    fill_n(out, n-width, " ");
    fill_n(out, width, " * ");
    cout << "\n";
}

Live demo .

Python live demo for reference.