I try to desalinize from XML to object. When i try to execute this code i get this inner exception get error message was not expected. . Please help me. Thank you for all reply.
<?xml version="1.0" encoding="UTF-8"?>
<result>
<status>
<interfaceId>shop.shipping.segment.get</interfaceId>
<systemStatus>OK</systemStatus>
<message>OK</message>
<requestId>714a4983-555f-42d9-aeea-89dae89f2f55</requestId>
<requests>
<id>1</id>
<kbnId>1</kbnId>
</requests>
</status>
<tns:shopMngApiResponse xmlns:tns="http://rakuten.co.jp/rms/mall/shop/mng/api/model/resource">
<resultCode>N000</resultCode>
<resultMessageList>
<resultMessage>
<code>N000</code>
<message>Succeeded.</message>
</resultMessage>
</resultMessageList>
<result xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:type="tns:soryoKbnResourceModel">
<soryoKbnList>
<soryoKbn>
<shopId>202317</shopId>
<kbnId>1</kbnId>
<id>1</id>
<name>test name 1</name>
</soryoKbn>
<soryoKbn>
<shopId>202317</shopId>
<kbnId>2</kbnId>
<id>7</id>
<name>test name 2</name>
</soryoKbn>
</soryoKbnList>
</result>
</tns:shopMngApiResponse>
</result>
Source Code: https://app.box.com/s/mmuk2ndkmz4llb71ryw81rpzca9mrmge
When deserializing into the "result"- object set the property as following:
[XmlElement(ElementName = "result", Form = XmlSchemaForm.Qualified)]
public YOURRESULTOBJECT result { get; set; }
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