How to write hive script for return result in shell variable in an Oozie coordinator?

Question

Then i coordinate my script.sh in an Oozie there is nothing in a variables S. Here is shell script

S=$(hive -S -hiveconf MY_VAR1=$DB -hiveconf MY_VAR2=$avgpay -hiveconf MY_VAR3=$Date_LastDay -hiveconf MY_VAR4=$Date_LastNmonth -f bpxp.hql)

echo $S "S"


S1=( $( for k in $S ; do echo $k ; done ) )
    cntn=${#S1[@]}
    for (( p=0 ; p<$cntn; p=p+5 ))
 do
     `mysql -h$mysqlhost -u$mysqluser -p$mysqlpass $mysqldb -e "INSERT INTO weekstat (timeshift, partnerid, avg_value, processdate, weekday) VALUES ('${S1[p]}', '${S1[p+1]}', '${S1[p+2]}', '${S1[p+3]}', '${S1[p+4]}');"`
done

Mysql commands works fine with another variables Here is bpxp.hql

...

    hive -e "select * from ${hiveconf:MY_VAR1}.weekstat;"

Then i run script from shell it works fine. I try to use bpxp.hql without this line hive -e "select * from ${hiveconf:MY_VAR1}.weekstat;" and write it in shell S= hive -e "select * from $DB.weekstat;" but nothing change. Where is my mistake?

Answer 1

Whatever you done is an efficient way, but minor change as mentioned below:

S=$(hive -S -hiveconf MY_VAR1=$DB -hiveconf MY_VAR2=$avgpay -hiveconf MY_VAR3=$Date_LastDay -hiveconf MY_VAR4=$Date_LastNmonth -f bpxp.hql)

In bpxp.hql keep the query

select * from $DB.weekstat;

You don't need to mention hive -e in the hql script, the command above will automatically executes and gives you the output, and stores into S.

Please let me correct if I'm wrong.