Python how to get parameters from bat file

Question

I have requirement to copy files from source to destination in python file. used

distutils.dir_util.copy_tree(src_dir,dest1_dir); 
distutils.dir_util.copy_tree(src_dir,dest2_dir);

src_dir , dest1_dir and dest2_dir are hard coded in the python file as

src_dir =/xx/ttt/yyy
dest1_dir=/xx/yyy/uuuu

But don't want hard code. I am calling this python script from abc.bat file

how to pass src_dir , dest1_dir , dest2_dir to python script from bat file and in python script how to get the passed parameters from the bat script. so that I replace the src and destination directory in the copy tree.

Answer 1

If you want to do something fast @AdamSmith's approach will be great.

On the other hand, if your program will grow a lot on options or you want to create more elegant parameters such as:

your_script --src-dir= src_dir --dest-dir= dest_dir

you can use argparse which will do the job great.

Even more, if you want to print something like this:

$ python copier.py -h
usage: copier.py [-h] [--src-dir] [--dest-dir] 

Copies a directory from source to destination

positional arguments:
--src-dir The source directory
--dest-dir The destination directory

optional arguments:
 -h, --help  show this help message and exit

Answer 2

You can access the whole argument values list with

import sys

sys.argv

the first element is always the name of the file, so you're looking at sys.argv[1:]

src, dst = sys.argv[1:]

But is there some reason that you're using the distutils module for this? It's more often called from shutil

import shutil
import sys

src, dst = sys.argv[1:]
try:
    shutil.copytree(src, dst)
    # shutil.copytree(src, dst2)  # how are you generating dst2?
except Exception:
    # something went wrong. Unless there's a reasonable way to recover we should just
    raise