Regex - use matching group

Question

I have written a regex

 0[\.\-/]0[\.\-/]0

to compare following patterns;

• 0.0.0
• 0-0-0
• 0/0/0

But it also matches

• 0.0-0

That I don't want. So is there any way to match the already matched sequence?

 0[\.\-/]0@10

Answer 1

0([./-])0\\1(0)

You will have to use group and then backreference it using \\1 .See demo.

https://regex101.com/r/mG8kZ9/3

Answer 2

Yes, as your title says perfectly: groups. Also called captures. Plain parentheses will capture the submatches; backslash-with-number will refer to the captures in order.

0([\.\-/])0\{1}0

or

0([\.\-/])0\1[0]

(because \\10 is something else, so we need to use alternate syntaxes or delimit them properly). \\1 (or \\{1} ) refers to the content between the first open plain parenthesis (ie not (?:...) , not (?=...) , just (...) ) and its matching closing one.

Answer 3

您可以尝试使用以下组：（0.0.0）|（0/0/0）|（0-0-0）