I have a json object which stores all the vehicle models with their brand.
[{
"brand":"Audi","model":"A4"
},
{
"brand":"Audi","model":"A6"
},
{
"brand":"BMW","model":"Z4"
},
{
"brand":"Audi","model":"R8"
},
{
"brand":"Volvo","model":"v40"
},
{
"brand":"BMW","model":"5 Series"
}]
But the problem is , If I have 3 models for Audi, then the list is repeating the brand again and again thus filling my list with duplicate values. So I need to make a json object something like this: I just want to make a json object as follows using javascript or angularjs:
[ {"brand":"Audi","models":["A4","A6","R8"]},
{"brand":"BMW","models":["Z4","5 Series"]},
{"brand":"Volvo","models":["v40"]}]
Given your input:
var input = [{
"brand": "Audi",
"model": "A4"
}, {
"brand": "Audi",
"model": "A6"
}, {
"brand": "BMW",
"model": "Z4"
}, {
"brand": "Audi",
"model": "R8"
}, {
"brand": "Volvo",
"model": "v40"
}, {
"brand": "BMW",
"model": "5 Series"
}];
you can achieve your desired result using Array.reduce -
var output = input.reduce(function(work, datum) {
var n = work.brands.indexOf(datum.brand);
if (n < 0) {
n = work.brands.push(datum.brand) - 1;
work.result.push({brand: datum.brand, models: []});
}
work.result[n].models.push(datum.model);
return work;
}, {brands:[], result:[]}).result;
you can make the JSON easily using both angular js or javascript. You can use following method in angular js . In javascript just use same type of loop like 'for'.
var model = {};
var brandList = [];
var returnObject = [];
var data = [
{
"brand": "Audi", "model": "A4"
},
{
"brand": "Audi", "model": "A6"
},
{
"brand": "BMW", "model": "Z4"
},
{
"brand": "Audi", "model": "R8"
},
{
"brand": "Volvo", "model": "v40"
},
{
"brand": "BMW", "model": "5 Series"
}
]
angular.forEach(data, function (dat, index) {
if (brandList.indexOf(dat.brand) == -1) {
brandList.push(dat.brand);
model[dat.brand] = [];
model[dat.brand].push(dat.model);
} else {
model[dat.brand].push(dat.model);
}
});
angular.forEach(brandList, function (val, index) {
var obj = {};
obj.brand = val;
obj.models = model[val];
returnObject.push(obj);
});
Now returnObject will hold your desired JSON object.
var input = [{
"brand": "Audi",
"model": "A4"
}, {
"brand": "Audi",
"model": "A6"
}, {
"brand": "BMW",
"model": "Z4"
}, {
"brand": "Audi",
"model": "R8"
}, {
"brand": "Volvo",
"model": "v40"
}, {
"brand": "BMW",
"model": "5 Series"
}];
// collect all brands models in a map
var brands_models = {};
for(var i=0; i < input.length; i++) {
var dat = input[i];
brands_models[dat.brand] = brands_models[dat.brand] || [];
brands_models[dat.brand].push(dat.model);
}
// make array from map
var output = [];
foreach(var brand in brands_models) {
output.push({
"brand" : brand,
"models": brands_models[brand]
});
}
A proposal with only Array.prototype.forEach
and Array.prototype.some
.
var data = [{ "brand": "Audi", "model": "A4" }, { "brand": "Audi", "model": "A6" }, { "brand": "BMW", "model": "Z4" }, { "brand": "Audi", "model": "R8" }, { "brand": "Volvo", "model": "v40" }, { "brand": "BMW", "model": "5 Series" }], combined = []; data.forEach(function (a) { !combined.some(function (b) { if (a.brand === b.brand) { !~b.model.indexOf(a.model) && b.model.push(a.model); return true; } }) && combined.push({ brand: a.brand, model: [a.model] }); }) document.write('<pre>' + JSON.stringify(combined, 0, 4) + '</pre>');
I suggest another optimum way:
var arr = [ { "brand": "Audi", "model": "A4" }, { "brand": "Audi", "model": "A6" }, { "brand": "BMW", "model": "Z4" }, { "brand": "Audi", "model": "R8" }, { "brand": "Volvo", "model": "v40" }, { "brand": "BMW", "model": "5 Series" } ]; var copy = arr.slice(0); var res = []; while (copy.length) {//it stop when copy is empty var a = {models: []};//create object var item = copy.shift();//item = copy[0], then copy[0] has deleted a.brand = item.brand;//current brand a.models.push(item.model);//first model has added copy.forEach(function (e, i) { if (e.brand === a.brand) {//find other items which they equal current brand a.models.push(e.model);//another models have added to models copy.splice(i, 1);//copy[i] has deleted } }); res.push(a);//current brand item has added } console.log(res);
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