I have a TextBox (txtDocUpload) and a Button. On the clicking of that button, an upload dialogue is opening and after uploading a file I have to save it in a particular folder.
For opening the upload dialogue
private void txtBtnUpload_Click_1(object sender, RoutedEventArgs e)
{
OpenFileDialog openFileDialog = new OpenFileDialog();
//openFileDialog.DefaultExt = ".txt";
Nullable<bool> result = openFileDialog.ShowDialog();
if (result == true)
{
filename = openFileDialog.FileName;
txtDocUpload.Text = System.IO.Path.GetFileName(filename);
}
}
Clicking save button I have to save, and the code ("File1"is the location where i want to save the file).
string urlpath = "WoDocs";
var path = @"~\" + urlpath + @"\" + WOMaintenance.GetAddressId.IDWorkOrderDetail;
if (!Directory.Exists(path))
Directory.CreateDirectory(path);
var ext = System.IO.Path.GetExtension(txtDocUpload.Text);
var pathURL=txtDocDescription.Text+ext;
var file1 = System.IO.Path.Combine(path,txtDocDescription.Text + ext);
//docFile1.SaveAs(file1);
Here is a brief example:
private void CopyAFile()
{
var source = new OpenFileDialog();
if (source.ShowDialog().GetValueOrDefault())
{
var dest = new SaveFileDialog();
if (dest.ShowDialog().GetValueOrDefault())
{
File.Copy(source.FileName, dest.FileName);
}
}
}
This should demonstrate that File.Copy does work when you have access to the source and destination locations.
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