Spring Boot not obeying command line arguments

Question

Put together a very basic Spring Boot RESTful backend with some CRUD endpoints. Trying to start it up on my Centos7 server. However I already have an application listening on its default port, 8080, so I have to configure that.

I have tried:

java -jar target/rest-1.0-SNAPSHOT.jar --server.port=8090

java -jar target/rest-1.0-SNAPSHOT.jar --Dserver.port=8090

java -jar target/rest-1.0-SNAPSHOT.jar --port=8090

java -jar target/rest-1.0-SNAPSHOT.jar --Dport=8090

My application.properties contains the line:

server.port=${port:8090}

Spring Boot still starts up the embedded Tomcat container on port 8080. It's not getting the message. What am I missing?

Edit: setting SERVER_PORT=8090 was effective - see below

Answer 1

Try with -Dserver.port=8090 note single - or server.port=xxxx in application.properties file

EDIT:-

Check your log, below line will echo in console 2015-10-16 23:13:23.082 INFO 4228 --- [ main] sbcetTomcatEmbeddedServletContainer : Tomcat initialized with port(s): 8090 (http)

VM arg overrides application.properties

Answer 2

If you have a "application.yml" or "application.properties" in the same folder of jar, the jar will take preference of the external configuration file. Doesnt make sense for me, but its true. The springboot has higher priority to external configuration file instead the internal one.

Answer 3

We have four different ways to change default port.

1. Using application.properties or application.yml
2. Implementing EmbeddedServletContainerCustomizer interface
3. Using SpringApplication class
4. Change port directly through command line

For more details, visit below http://www.javainterviewpoint.com/spring-boot-change-embedded-tomcat-default-port/