Operator Function Called Infinite

Question

I am getting runtime error, Could anyone figure out why there is an infinite call in this programme and which line is doing it

http://ideone.com/0CWZTD

Here goes my Code

class opOverload{
public:
    bool operator==(opOverload temp){
        if(*this == temp){
            cout << "both same";
            return true;
        }
        else{
            cout <<"both different";
            return false;
        }
    }
};


int main() {
    // your code goes here
    opOverload a1,a2;
    a1==a2;
    return 0;
}

Answer 1

因为*this == temp等价于(*this).operator==(temp) ，它显然调用了你刚刚写的同一个operator== 。

Answer 2

*this == temp

will again invoke your operator overload, so you are basically doing:

A(){
   A();
}

This is a self recursive function call, and you are obviously not making progress (towards the base case, even worse...there is no base case)