Group by several results SQL Oracle

Question

I'd like to have a result grouped by a propertie.

Here's an example about what I would like to retrieve:

And here's come the table definition :

I tried this but it does not work :

SELECT      OWNER.NAME, DOG.DOGNAME
WHERE       OWNER.ID = DOG.OWNER_ID
AND         OWNER.NAME = (SELECT OWNER.NAME FROM OWNER);

But it returns me an error:

1427. 00000 - "single-row subquery returns more than one row"

Thanks a lot !

Answer 1

I am not Oracle expert, but I believe you need FROM and JOIN part :-) :

http://sqlfiddle.com/#!4/f8630/1

SELECT      OWNER.ID, OWNER.NAME,
            DOG.ID, DOG.DOGNAME
FROM        OWNER
LEFT JOIN   DOG
ON          OWNER.ID = DOG.OWNER_ID;

Answer 2

根据Alex的响应进行编辑 ，查询的修改版本为：

SELECT OWNER.NAME, DOG.DOGNAME FROM OWNER LEFT JOIN DOG ON OWNER.ID = DOG.OWNER_ID ORDER BY OWNER.NAME

Answer 3

First up, you are missing the table clauses:

And if you put those in, you still have a problem if you have multiple owners with the same name, where the sub-select in the where clause is returning multiple rows:

---

AND OWNER.NAME = (SELECT OWNER.NAME FROM OWNER);

If NAME is not distinct, this raises the error.

You could change it to:

AND OWNER.NAME IN (SELECT OWNER.NAME FROM OWNER);

Although in this case the entire clause is meaningless as the whole table will always be returned

Final answer:

SELECT      OWNER.NAME, DOG.DOGNAME
FROM        OWNER, DOG
WHERE       OWNER.ID = DOG.OWNER_ID;