An array of integers

Question

public static boolean have(int x, int count) {
    int i;
    count = 1;
    for (i = 0; i < array.length; i++) {
        if (x >= 1) return true;
    }
    return false;
}

Boolean method returns true if there are at least the given quantity of the given number in the structure.

Answer 1

You need to first count the times the element occurs in your array. Using a for-each loop , that might look something like

int vcount = 0;
for (int val : array) {
    if (x == val) {
        vcount++;
        if (vcount >= count) return true;
    }
}
return false;

or

return vcount >= count; // <-- to handle count == 0.

Answer 2

If you want to search for specific element in an array:

if (arrray[i] == x) {
    return true;
}

Your code returns true if the first argument of the have method is >= 1