I have a 2 vectors of size 4 to store coordinates of a shape (square/rectangle). 1st vector is for x and 2nd for y. To find out the area of the shape, I need the difference in their length. How do I find the difference between 2 elements within the same vector? Using square as an example:
vector<int> x(4);
vector<int> y(4);
double Square::computeArea()
{
int length;
double area;
if (x[0] == x[1]) //x coordinates are the same
{
length = y[0] - y[1]; //difference in y coordinates to find the length, need help here
}
else if (x[1] == x[2]
{
length = y[1] - y[2];
}
else if ... //repeat
area = length * length;
if (area < 0) { area = -area; }
setArea(area)
return area;
}
If your rectangle has edges which are parallel to the axis, and the points are ordered clockwise (or counterclockwise), you can simply use the first and third element of the arrays:
int yedge, xedge;
xedge = abs(x[0] - x[2]);
if ( xedge == 0 ) //beware, this check works well only for ints!
return area = 0.0;
else yedge = abs(y[0] - y[2]);
return area = xedge * yedge;
If you have more general convex quadrilaterals use something like this:
int dx20 = x[2] - x[0];
int dy10 = y[1] - y[0];
int dy20 = y[2] - y[0];
int dx10 = x[1] - x[0];
int dy30 = y[3] - y[0];
int dx30 = x[3] - x[0];
area = 0.5*abs(dx20*dy10-dy20*dx10);
area += 0.5*abs(dx20*dy30-dy20*dx30);
The beauty of C++ and OOP is that you can think more in terms of the problem than how to program it.
If I were in your place I would use std::pair to save the coordinates.
And have a class representing the rectangle.
I am using the distance between point 1 and 2 as length, and point 1 and 4 as width. It may not be the correct approach in all cases but it should show you have to go about programming your function.
using namespace std;
class Rectangle // Class Rectangle
{
public:
Rectangle(vector<pair<double, double>> neWcoordinates);
double computeArea();
private:
vector<pair<double, double>> coordinates;
};
double Rectangle::computeArea()
{
double length = sqrt(pow(coordinates[0].first-coordinates[1].first,2)+pow(coordinates[0].second-coordinates[1].second,2)
);
double width = sqrt(pow(coordinates[0].first-coordinates[3].first,2)+pow(coordinates[0].second-coordinates[3].second,2));
return length*width;
}
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