I deploy the Hadoop-Spark cluster and run my job. Through the submit script bin/spark-submit, i can success submit the spark jobs. Now, I want to catch the tracking URL just like http://hadoop-01:8088/proxy/application_1446625315279_0017/ and use it in my other scala project. How can i do that? i try to rediect the spark-submit output, but it seems don't work, just like
./bin/spark-submit --class org.apache.spark.examples.mllib.JavaKMeans --master yarn-cluster --num-executors 32 --executor-cores 4 --executor-memory 16G --driver-memory 8G lib/spark-examples-1.4.0-hadoop2.6.0.jar /data/kmeans_data.txt 100 9 >> log.log
But after finish, the log.log still empty.
Another, i try to use scala.sys.process.ProcessIO to catch the spark-submit output, it don't work as i want.Here is the code:
def submitSparkJob(filename: String) = {
val baseCmd = """/opt/spark-1.4.0-bin-hadoop2.6/bin/spark-submit
| --master yarn-cluster
| --num-executors 32 --executor-cores 4 --executor-memory 16G
| --driver-memory 8G""".stripMargin.replace("\n", " ")
val jarEntry = " --class org.apache.spark.examples.mllib.JavaKMeans "
val jarFile = " /opt/spark-1.4.0-bin-hadoop2.6/lib/spark-examples-1.4.0-hadoop2.6.0.jar"
val pramas = " /data/" + filename + " 1000 9"
val cmd = baseCmd + jarEntry + jarFile + pramas
val pb = Process(cmd)
val pio = new ProcessIO(_ => (),
stdout => scala.io.Source.fromInputStream(stdout)
.getLines.foreach(println),
_ => ())
pb.run(pio)
}
I can see nothing output in the terminator. How can i get the spark job's "tracking URL" and use it in my scala code ? Thank you !
Oh, my god! bin/spark-submit display on the terminator is error information. So, use ./bin/spark-submit args 2>>log.txt to redirect, or change the scala code to:
val pio = new ProcessIO(_ => (),
_ => (),
err => scala.io.Source.fromInputStream(err)
.getLines.foreach( line =>
if(pattern.findFirstMatchIn(line) != None){
result = line
println(line)
}
)
)
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