IPv4 address with PHP

Question

I want to get the IPv4 address, but not the localhost address (127.0.0.1). I just get ::1.

i tried it with $ip = getenv ("REMOTE_ADDR");

and

$ip = getenv ('SERVER_ADDR');

Answer 1

$ip = $_SERVER['REMOTE_ADDR'];

Answer 2

Finally i got the answer at the same day. You can see it below:

    function getIP() {
    $ip = $_SERVER['SERVER_ADDR'];

    if (PHP_OS == 'WINNT'){
        $ip = getHostByName(getHostName());
    }

    if (PHP_OS == 'Linux'){
        $command="/sbin/ifconfig";
        exec($command, $output);
        // var_dump($output);
        $pattern = '/inet addr:?([^ ]+)/';

        $ip = array();
        foreach ($output as $key => $subject) {
            $result = preg_match_all($pattern, $subject, $subpattern);
            if ($result == 1) {
                if ($subpattern[1][0] != "127.0.0.1")
                $ip = $subpattern[1][0];
            }
        //var_dump($subpattern);
        }
    }
    return $ip;
}

Answer 3

您可以使用gethostbyname()获得 IPv4 地址，例如使用gethostbyname($_SERVER['HTTP_HOST']) 。