I have a set of values in a csv file. The values are shown below.I want those values to be sorted by a layer column, that has values 7208 and 7209 in the example below. Otherwise I want the csv file to be exactly as it is. My code below doesn't seem to sort it correctly.
Here's the csv file:
l_d,l_t,utc,SI,UTC,La,Lon,H,layer,N,Pr,EId,Pype,BS,Vo,Te,Chs,PT,Pass
01-08,11:00:19,03:00:19,0x037,01-08_02:58:03,None,None,None,7208,None,None,None,None,87,15.4,None,None,None,MENT
01-08,11:00:19,03:00:19,0x037,01-08_02:58:03,None,None,None,7209,None,None,None,None,87,15.4,None,None,None,MENT
Here's my current code:
import sys
import csv
import operator
reader = csv.reader(open("M_B.csv"), delimiter=",")
sortedlist = sorted(reader, key=operator.itemgetter(9), reverse=True)
print(sortedlist)
with open("M_B_Sorted.csv", "wb") as f:
writer = csv.writer(f)
writer.writerows(sortedlist)
First, the index is wrong. It should be 8
.
And you need to convert the string to int
; cannot be done solely with itemgetter
:
sortedlist = sorted(reader, key=lambda row: int(row[8]), reverse=True)
In addition to that, you need to exclude header.
import csv
with open("M_B.csv") as fin, open("M_B_Sorted.csv", "wb") as f:
reader = csv.reader(fin, delimiter=",")
writer = csv.writer(f)
header = next(reader) # <--- Pop header out
writer.writerow(header) # <--- Write header
sortedlist = sorted(reader, key=lambda row: int(row[8]), reverse=True)
writer.writerows(sortedlist)
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