Tensorflow indexing with boolean tensor

Question

In numpy, with two arrays of the same shape, x and y , it is possible to do slices like this y[x > 1] . How do you achieve the same result in tensorflow? y[tf.greater(x, 1)] doesn't work and tf.slice doesn't support anything like this either. Is there a way to index with a boolean tensor right now or is that currently unsupported?

Answer 1

Try:

ones = tf.ones_like(x) # create a tensor all ones
mask = tf.greater(x, ones) # boolean tensor, mask[i] = True iff x[i] > 1
slice_y_greater_than_one = tf.boolean_mask(y, mask)

See tf.boolean_mask

EDIT : another (better ?) way to do it:

import tensorflow as tf

x = tf.constant([1, 2, 0, 4])
y = tf.Variable([1, 2, 0, 4])
mask = x > 1
slice_y_greater_than_one = tf.boolean_mask(y, mask)

with tf.Session() as sess:
    sess.run(tf.global_variables_initializer())
    print (sess.run(slice_y_greater_than_one)) # [2 4]

Answer 2

I would not say it is completely not implemented. How's that for a double negative?

Tensorflow actually supports quite a lot of slicing and dicing, although the syntax may be slightly less pretty. For example, if you want to create a new array which is equal to y when x>1 but equal to 0 otherwise, you can definitely do that. Check out comparison operators eg

masked = tf.greater(x,1)
zeros = tf.zeros_like(x)
new_tensor = tf.where(masked, y, zeros)

If, on the other hand, you want to make a new array which contains only the guys where x>1 you can do that by combining where with the gather function. Details for gather can be found at

https://www.tensorflow.org/versions/master/api_docs/python/array_ops/slicing_and_joining

PS. Of course, x>1 is not differentiable with respect to x ... tf may be great, but it doesn't work magic :).

Answer 3

目前尚未实现，这是跟踪进度的GitHub问题 - https://github.com/tensorflow/tensorflow/issues/206

Answer 4

tf.boolean_mask does the job, but on some platforms like Raspberry Pi or OSX, the operation is not supported in Tensorflow wheel distributions (Check this tf.boolean_mask not supported on OSX . So an alternative is to use where and gather as @Jackson Loper suggested. For example:

x = tf.Variable([1, 2, 0, 4])
ix = tf.where(x > 1)
y = tf.gather(x, ix)

with tf.Session() as sess:
 sess.run(tf.global_variables_initializer())
 print(sess.run(y))

Answer 5

Was looking for similar capability to reduce a TensorFlow.js tensor by a defined criteria, but TensorFlow.js does not have the boolean_mask function. After much hair pulling and teeth gnashing, cooked up the following, which essentially sums up the total number of true criteria, and then simply selects the topk values to create the subset tensor.

const a = tf.tensor1d([1, 2, 0, 4]);
const b = a.greater(1).sum().get();
const {values, indices} = tf.topk(a, b);
values.print();   # 4,2
indices.print();  # 3,1

And to create a subset tensor of values less than or equal to 1, it's a matter of using tf.neg on the tensor as there is no bottomk function, and then after obtaining the subset tensor via topk, applying tf.neg again to restore the original values.