How to pass as parameter a function that has parameters defined by default without passing them? C++

Question

I have this code

void foo(int Var1, int Var2, int default1=10, int defaul2=10);
void bar(int Var1, int Var2);
someFunction(void (*foobar)(int, int));
otherFunction(void (*foobar)(int, int, int, int));

int main(){
    someFunction(foo); //ERROR
    otherFunction(bar); //ERROR
}

So, i want to choose between foo and bar on the same function ignoring the default parameters, but i don't know how to do it.

Answer 1

It won't work because foo's function signature doesn't correspond to what someFunction expects. The default parameters in foo don't make the parameters go away, it just fills it with a default value at compile time.

You could try casting foo and see what that gives you.

typedef void (*twoParameterFunctionType)(int, int);

someFunction((twoParamterFunctionType)foo);