C - segmentation fault and strlen

Question

I've been trying to figure out this segmentation fault for hours. Every time I use the char* find I get a seg fault.

char* find = malloc(sizeof(char) * 20);

displayMatrix(rowcol, matrix);
// (Don't mind that ^^^)

printf("Enter a word to find in the puzzle : \n");
scanf("%s", &find);
tolower(find);
len = strlen(find) + 1;

When I run the program, it seg faults right as it gets to

len = strlen(find) + 1

Anyone know why it's doing this? Thanks in advance.

Answer 1

scanf("%s", &find); should be scanf("%s", find); find is already the address of the string.

and tolower is incorrect, too: int tolower ( int c ); not int tolower ( char *c );

Answer 2

Other way to do it would be point to a string literal using const char * and changing the rest of the code as:

const char* find = (char*) malloc(sizeof(char)*20);
printf("Enter a word to find in the puzzle : \n");
scanf("%s", find);
printf("find says : I have got this saved under me %s \n", find); //just tried checking if it works
tolower(find); //this surely needs some correction,determine what you want
int len = strlen(find); //you won't require +1 using strlen
printf("%d : It Works Fine.",len);