I have this table with some sample data:
Supplier_ID Product_ID Stock
-----------------------------
1 272 1
1 123 5
1 567 3
1 564 3
2 272 4
2 12 3
2 532 1
3 123 4
3 272 5
I want to check the suppliers that have both products: 272
and 123
, so the result would be like:
Supplier_ID
-----------
1
3
You can use GROUP BY
and HAVING
:
SELECT Supplier_ID
FROM your_tab
WHERE Product_ID IN (272, 123)
GROUP BY Supplier_ID
HAVING COUNT(DISTINCT Product_ID) = 2;
Try this code:
SELECT A.Supplier_ID FROM
(SELECT Supplier_ID FROM Your_Table WHERE Product_ID = 272) AS A
INNER JOIN
(SELECT Supplier_ID FROM Your_Table WHERE Product_ID = 123) AS B
ON A.Supplier_ID = B.Supplier_ID
This is how it works using set operations . IMHO a too little used feature of databases.
select Supplier_ID from table1 where product_id=272
intersect
select Supplier_ID from table1 where product_id=123
it produces as well
Supplier_ID
1
3
By the way a distinct is not needed due to intersect delivers distinct rows.
Try This Code: By Using Row_number()
;WITH cte
AS (SELECT *,
Row_number()
OVER(
partition BY [Supplier_ID]
ORDER BY [Supplier_ID]) AS rn
FROM #Your_Table
WHERE Product_ID IN ( 272, 123 ))
SELECT DISTINCT Supplier_ID
FROM cte
WHERE rn > 1
OUTPUT :
Supplier_ID
1
3
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