I have a CSV file that I'm reading in Python and I want the program to skip over the row if the first column is empty. How do I do this?
Right now I have:
with open('testdata1.csv', 'rU') as csvfile:
csvreader = csv.reader(csvfile)
for row in csvreader:
if row[0] = null:
#?????
How do I: 1) Check for empty cells in the CSV; and 2) tell the reader to skip the row?
Thanks guys.
with open('testdata1.csv', 'r') as csvfile:
csvreader = csv.reader(csvfile)
for row in csvreader:
print(row)
if not row[0]:
print("12")
Reference: How do I detect missing fields in a CSV file in a Pythonic way?
You could use try and except.
for row in csvreader:
try:
#your code for cells which aren't empty
except:
#your code for empty cells
After hour of trying I was able to do it
while act_tab.cell(row=i, column=1).value is not None:
...
Small adaptation of Kit Fung's answer:
with open('testdata1.csv', 'r') as csv_file:
csv_reader = csv.reader(csv_file)
for row in csv_reader:
if not row[0]:
continue # this will skip to the next for loop iteration
# do your processing here
我会假设如果你len()
那么它将为零,即
if not len(row[0])
I tried out what happens if you print and empty row and it returns [] (empty brackets)... so just check for that.
with open('testdata1.csv', 'rU') as csvfile:
csvreader = csv.reader(csvfile)
for row in csvreader:
if row == []:
continue
#do stuff normally
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