File URL "Not allowed to load local resource" in the Internet Browser

Question

I've got a major brainteaser.

I want to open a file in classic ASP. I'm using various variables because things can change but the outcome is correct. I know this because I've tested the outcome by copying the linkadress and placing it in my URL. Now the problem: If I click my link it doesn't do anything. Not a refresh, not a redirect. nothing. Does anyone know what I did wrong?

Ok here's the deal. My file isn't always local, it depends on what environment I'm on. If I copy-paste the outcome of my url it does download. If I click my URL it doesn't respond. Any ideas? Browser problem? (although I've tested 5 browsers) Or anything else? I'm really stuck here and the internet does not seem to be on my side.

I've got 3 environments. The variables underneath here are so that the link works. I know the link works because I've tested it by copying. And yes, it does begin with file:/// and yes I'm sure the link is right.

Here's my line of code:

response.write("<td class='tab_kolom2'><a href='"&rootRs("pre_rootpad")&rootRs("rootpad_protocollen")&"\"&overzichtRs("Formuliernr")&"\Uitvoeringsoverzicht.xls' target='_blank' download>Click here</a></td>")

---

EDIT: Screenshot with error/outcome of link

Answer 1

Now we know what the actual error is can formulate an answer.

Not allowed to load local resource

is a Security exception built into Chrome and other modern browsers. The wording may be different but in some way shape or form they all have security exceptions in place to deal with this scenario.

In the past you could override certain settings or apply certain flags such as

--disable-web-security --allow-file-access-from-files --allow-file-access

in Chrome (See https://stackoverflow.com/a/22027002/692942 )

It's there for a reason

At this point though it's worth pointing out that these security exceptions exist for good reason and trying to circumvent them isn't the best idea.

There is another way

As you have access to Classic ASP already you could always build a intermediary page that serves the network based files. You do this using a combination of the ADODB.Stream object and the Response.BinaryWrite() method. Doing this ensures your network file locations are never exposed to the client and due to the flexibility of the script it can be used to load resources from multiple locations and multiple file types.

Here is a basic example ("getfile.asp"):

<%
Option Explicit

Dim s, id, bin, file, filename, mime

id = Request.QueryString("id")

'id can be anything just use it as a key to identify the 
'file to return. It could be a simple Case statement like this
'or even pulled from a database.
Select Case id
Case "TESTFILE1"
  'The file, mime and filename can be built-up anyway they don't 
  'have to be hard coded.
  file = "\\server\share\Projecten\Protocollen\346\Uitvoeringsoverzicht.xls"     
  mime = "application/vnd.ms-excel"
  'Filename you want to display when downloading the resource.
  filename = "Uitvoeringsoverzicht.xls"

'Assuming other files 
Case ...
End Select

If Len(file & "") > 0 Then
  Set s = Server.CreateObject("ADODB.Stream")
  s.Type = adTypeBinary 'adTypeBinary = 1 See "Useful Links"
  Call s.Open()
  Call s.LoadFromFile(file)
  bin = s.Read()

  'Clean-up the stream and free memory
  Call s.Close()
  Set s = Nothing

  'Set content type header based on mime variable
  Response.ContentType = mime
  'Control how the content is returned using the 
  'Content-Disposition HTTP Header. Using "attachment" forces the resource
  'to prompt the client to download while "inline" allows the resource to
  'download and display in the client (useful for returning images
  'as the "src" of a <img> tag).
  Call Response.AddHeader("Content-Disposition", "attachment;filename=" & filename)
  Call Response.BinaryWrite(bin)
Else
  'Return a 404 if there's no file.
  Response.Status = "404 Not Found"
End If
%>

^{This example is pseudo coded and as such is untested.}

This script can then be used in <a> like this to return the resource;

<a href="/getfile.asp?id=TESTFILE1">Click Here</a>

The could take this approach further and consider (especially for larger files) reading the file in chunks using Response.IsConnected to check whether the client is still there and s.EOS property to check for the end of the stream while the chunks are being read. You could also add to the querystring parameters to set whether you want the file to return in-line or prompt to be downloaded.

---

Useful Links

• Using METADATA to Import DLL Constants - If you are having trouble getting adTypeBinary to be recongnised, always better then just hard coding 1 .

• Content-Disposition:What are the differences between “inline” and “attachment”? - Useful information about how Content-Disposition behaves on the client.

Answer 2

For people do not like to modify chrome's security options, we can simply start a python http server from directory which contains your local file:

python -m SimpleHTTPServer

and for python 3:

python3 -m http.server

Now you can reach any local file directly from your js code or externally with http://127.0.0.1:8000/some_file.txt

Answer 3

You will have to provide a link to your file that is accessible through the browser, that is for instance:

<a href="http://my.domain.com/Projecten/Protocollen/346/Uitvoeringsoverzicht.xls">

versus

<a href="C:/Projecten/Protocollen/346/Uitvoeringsoverzicht.xls">

If you expose your "Projecten" folder directly to the public, then you may only have to provide the link as such:

<a href="/Projecten/Protocollen/346/Uitvoeringsoverzicht.xls">

But beware, that your files can then be indexed by search engines, can be accessed by anybody having this link, etc.

Answer 4

Follow the below steps,

1. npm install -g http-server, install the http-server in angular project.
2. Go to file location which needs to be accessed and open cmd prompt, use cmd http-server ./
3. Access any of the paths with port number in browser(ex: 120.0.0.1:8080) 4.now in your angular application use the path "http://120.0.0.1:8080/filename" Worked fine for me

Answer 5

I didn't realise from your original question that you were opening a file on the local machine, I thought you were sending a file from the web server to the client.

Based on your screenshot, try formatting your link like so:

<a href="file:///C:/Projecten/Protocollen/346/Uitvoeringsoverzicht.xls">Klik hier</a>

(without knowing the contents of each of your recordset variables I can't give you the exact ASP code)

Answer 6

You just need to replace all image network paths to byte strings in HTML string. For this first you required HtmlAgilityPack to convert Html string to Html document. https://www.nuget.org/packages/HtmlAgilityPack

Find Below code to convert each image src network path(or local path) to byte sting. It will definitely display all images with network path(or local path) in IE,chrome and firefox.

string encodedHtmlString = Emailmodel.DtEmailFields.Rows[0]["Body"].ToString();

        // Decode the encoded string.
        StringWriter myWriter = new StringWriter();
        HttpUtility.HtmlDecode(encodedHtmlString, myWriter);
        string DecodedHtmlString = myWriter.ToString();

        //find and replace each img src with byte string
         HtmlDocument document = new HtmlDocument();
         document.LoadHtml(DecodedHtmlString);
         document.DocumentNode.Descendants("img")
          .Where(e =>
        {
            string src = e.GetAttributeValue("src", null) ?? "";
            return !string.IsNullOrEmpty(src);//&& src.StartsWith("data:image");
        })
        .ToList()
                    .ForEach(x =>
                    {
                        string currentSrcValue = x.GetAttributeValue("src", null);                                
                        string filePath = Path.GetDirectoryName(currentSrcValue) + "\\";
                        string filename = Path.GetFileName(currentSrcValue);
                        string contenttype = "image/" + Path.GetExtension(filename).Replace(".", "");
                        FileStream fs = new FileStream(filePath + filename, FileMode.Open, FileAccess.Read);
                        BinaryReader br = new BinaryReader(fs);
                        Byte[] bytes = br.ReadBytes((Int32)fs.Length);
                        br.Close();
                        fs.Close();
                        x.SetAttributeValue("src", "data:" + contenttype + ";base64," + Convert.ToBase64String(bytes));                                
                    });

        string result = document.DocumentNode.OuterHtml;
        //Encode HTML string
        string myEncodedString = HttpUtility.HtmlEncode(result);

        Emailmodel.DtEmailFields.Rows[0]["Body"] = myEncodedString;