I have below method in which different date patterns have been handled
below is the method in which different date formats have been handled now
now for the particulat format YYYY-MM-dd i don't want it to go for the check where we are prefixing 20 before in code please advise how can i skip that part lets say if the date pattern is YYYY-MM-dd then avoid the logic of prefixing 20 in front of year
below is my code
public java.util.Date extractDate(String dateStr, String dateType) {
String[] datePatternsOfUk = { "d-M-yy", "d-M-yyyy", "d/M/yy", "d/M/yyyy", "yyyy-MM-dd","dd-MM-yy", "dd-MMM-yy","dd-MMM-yyyy","dd-MM-yyyy",
"dd/MM/yy","dd/MMM/yy","dd/MMM/yyyy"};
String[] datePatternsOfUs = { "M-d-yy","MM-dd-yy","M/d/yy","MM/dd/yy", "MM/dd/yy", "MMM-dd-yy",
"MMM/dd/yy", "MMM-dd-yyyy", "MM-dd-yyyy", "MMM/dd/yyyy",
"MM/dd/yyyy" };
java.util.Date date = null;
String[] datePatterns = datePatternsOfUk;
if (dateType.equals("US")) {
datePatterns = datePatternsOfUs;
} else if (dateType.equals("UK")) {
datePatterns = datePatternsOfUk;
}
///******code should not go in this check where date pattern is YYYY-MM-dd
int p = dateStr.lastIndexOf("/");
if (p == -1) {
p = dateStr.lastIndexOf("-");
}
String firstSubstring = dateStr.substring(0, p + 1);
String secondSubstring = dateStr.substring(p + 1);
if (p != -1 && secondSubstring.length() <= 2) {
secondSubstring = Integer.toString(2000 + Integer.parseInt(secondSubstring));
dateStr = firstSubstring + secondSubstring;
}
///****************************************//
try {
date = DateUtils.parseDate(dateStr, datePatterns);
} catch (ParseException ex) {
logger.error("##$$$$$### Error in invoice inside extractDate method : ##$$$$$$#### "
+ ErrorUtility.getStackTraceForException(ex));
}
return date;
}
You could avoid trying any inappropriate pattern by checking if the string "looks like" the pattern before parsing with the pattern.
The general way to do this is:
String datePattern = "yyyy-MM-dd"; // for example
String input;
if (input.matches(datePattern.replaceAll("\\w", "\\d"))) {
// the input looks like the pattern
// in this example "dddd-dd-dd" where "d" is any digit
// so go ahead and try the parse
}
You can enhance this logic to add:
if (input.matches("\\d\\d\\D.*")) {
// then it only has a two digit year, so add "20" to the front
}
if (!dateStr.equals("YYYY-MM-dd")) {
// code
}
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