I created a python egg by running python setup.py bdist_egg
from this folder:
SensorDisplay/
--- sensor_display/
----- __init__.py
----- can.py
----- sensor_display.py
----- data/
--------- sensor_param.txt
--- setup.py
in file setup.py
, I have:
package_data = {'' : ['*.txt']},
scripts = ['sensor_display/sensor_display.py','sensor_display/can.py']
and in file sensor_display.py
:
PARAM_FILE = "data/sensor_display.txt"
param_file = pkg_resources.resource_filename("sensor_display", PARAM_FILE)
f = open(param_file,"r")
I obtain then the egg file SensorDisplay-0.1-py2.7.egg
in folder SensorDisplay\\dist\\
. However, when I install the egg with easy_install and run the file C:\\Python27\\Scripts\\sensor_display.py
, I obtain the following error:
IOError: [Errno 2] No such file or directory: 'C:\\Python27\\lib\\site-packages\
\sensordisplay-0.1-py2.7.egg\\EGG-INFO\\scripts\\data\\sensor_param.txt'
It seems function resource_filename
doesn't extract the egg-file because the filename returned considers the egg-file as a directory which it is not.
I found the problem, I replaced
PARAM_FILE = "data/sensor_display.txt"
param_file = pkg_resources.resource_filename("sensor_display", PARAM_FILE)
with
PARAM_FILE = "sensor_display/data/sensor_display.txt"
param_file = pkg_resources.resource_filename(pkg_resources.Requirement.parse("SensorDisplay"), PARAM_FILE)
see also pkg_resources.resource_filename is not extracting files
egg file is a zip archive. You can look at the contents using unzip command.
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