I want to convert a decimal number (loop index number) in a bash script to hexadecimal to be used by another command. Something like:
for ((i=1; i<=100; i++))
do
a=convert-to-decimal($i)
echo "$a"
done
Where a should be hexadecimal with four digits and hex identifier. For example if value of i is 100 , the value of a should be 0x0064 . How to do it?
You can use printf
.
$ printf "0x%04x" 100
0x0064
In your example you'd probably use a="$(printf '0x%04x' $i)"
.
That's what you're looking for
for i in seq 1 100
; do printf '%x\\n' $i done
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