If i have the following code:
function myClass(){
this.type = 1;
this.ret = function(){
return this.type;
}
}
var ins1 = new myClass,
ins2 = new myClass,
ins3 = new myClass;
ins2.type = 2;
ins3.type = 3;
console.log(ins1.ret() + ' - ' + ins2.ret() + ' - ' + ins3.ret());
The output in the console is
1 - 2 - 3
When the code runs (the console.log()
part), is there one method ret()
running, or three? If each instance creates a new method, how can I avoid that? If they all do the same exact thing, why have three of them.
The methods are different indeed. You are wasting memory.
ins1.ret == ins2.ret; // false
Instead, you can define the method in the prototype:
function myClass(){}
myClass.prototype.type = 1;
myClass.prototype.ret = function(){
return this.type;
};
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