Function to find variance returns 0

Question

I'm working on a program for school that involves finding certain statistics of an array, and one of the things I have to find is the variance, I have a function made for it but for some reason it keeps returning 0

double variance(double * array, unsigned int size, double value)
{
    double variance = 0; //Variable used to store the variance
    for (unsigned int i = 0; i < size; ++i)
    {
        if (value > array[i]) //If statement checks to see if you need to subtract the value from the array or the other way around
        {
            variance += pow((value - array[i]), 2);
        }
        else
        {
            variance += pow((array[i] - value), 2);
        }
    }
    variance /= size; 
    return variance;
}

I've tried going through it with the debugger but I came out with nothing

how I called it:

double varaince = variance(array, size, mean);
printf("\nVariance: %.3lf", variance);

sample output

Answer 1

As @ammoQ commented

double varaince = variance(array, size, mean);

//                         function name used here.
// printf("\nVariance: %.3lf", variance);

//                       Use variable name
printf("\nVariance: %.3lf", varaince);

Answer 2

    variance/=size;

Should be

    variance/=(double)size;

size on its own is stored as a binary integer.