I have two tables blog and tbl_users. blog contains columns 'blogid','message','title','name','created' & 'image_ctgy'. tbl_users contains columns 'userPic', 'image_ctgy', 'userId'. The code below displays the blog message and the associated images with that blog messsage based on the same image_ctgy. However my knowledge of php is limited and I am having difficulty in displaying the title, name & created columns along with the blog message. Any help would be appreciated.
$sql = "SELECT blog.message as blogmessage, tbl_users.userPic as tblPics
FROM blog
LEFT JOIN tbl_users ON(blog.image_ctgy = tbl_users.image_ctgy)
ORDER by blog.blogid DESC";
$stmt = $db->prepare($sql);
$stmt->execute();
$blogs = array();
while (($row = $stmt->fetch(PDO::FETCH_ASSOC)))
{
$blogmessage = $row['blogmessage'];
$blogs[$blogmessage] [] = $row['tblPics'];
}
?>
<html>
<body>
<?php
foreach ($blogs as $blogmessage => $tblPics)
{
?>
<h2><?php echo $blogmessage; ?></h2>
<ul>
<?php
foreach ($tblPics as $tblPic)
{
?>
<li> <img src="cms3/user_images/<?php echo $tblPic; ?>"width="50px" height="50px"/></li>
<?php
}
?>
</ul>
<?php
}
?>
</body>
</html>
You can use this code to get fields title, name, created along with message and userPic:
<?php
$sql = "SELECT blog.message as blogmessage, blog.title, blog.name, blog.created, tbl_users.userPic as tblPics
FROM blog
LEFT JOIN tbl_users ON(blog.image_ctgy = tbl_users.image_ctgy)
ORDER by blog.blogid DESC";
$stmt = $db->prepare($sql);
$stmt->execute();
$blogs = array();
while (($row = $stmt->fetch(PDO::FETCH_ASSOC)))
{
// here you can get along with blogmessage another desired columns:
// title, name, created
$blogmessage = $row['blogmessage'];
$blogs[$blogmessage] [] = $row['tblPics'];
}
?>
<html>
<body>
<?php
foreach ($blogs as $blogmessage => $tblPics)
{
?>
<h2><?php echo $blogmessage; ?></h2>
<ul>
<?php
foreach ($tblPics as $tblPic)
{
?>
<li> <img src="cms3/user_images/<?php echo $tblPic; ?>"width="50px" height="50px"/></li>
<?php
}
?>
</ul>
<?php
}
?>
</body>
</html>
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