Using the object operator in PHP
Question
I looked at this post to try and understand the object operator better: Where do we use the object operator "->" in PHP?
But when I copied and pasted the php in the 2nd response, I just get a blank page when I run it. Here is my code:
PHP:
<?php
class SimpleClass
{
// property declaration
public $var = 'a default value';
// method declaration
public function displayVar() {
echo $this->var;
}
}
$a = new SimpleClass();
echo $a->var;
$a->displayVar();
?>
HTML:
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8" />
<title></title>
</head>
<body>
<form action ="process.php" method ="POST">
First Name: <input type="text" name="fName">
<input type="submit">
</form>
<p>
Click for objectOperator.php
<button onsubmit="objectOperator.php">Submit</button>
</p>
</body>
</html>
Ignore the form in the HTML, that was for something else I was doing. When I click on the Submit button I want to run the php in objectOperator.php (which is the name of my php file). But when I click it nothing happens.
1 answers
solution1
0 2016-03-07 04:37:21
You can try this
I just tried this on phpfiddle and it was working
<?php
class SimpleClass
{
// property declaration
public $var = 'a default value';
// method declaration
public function displayVar() {
echo $this->var;
}
}
if ($_SERVER['REQUEST_METHOD'] == 'POST')
{
$a = new SimpleClass();
echo $a->var;
$a->displayVar();
}
?>
<form action ="" method ="POST">First Name: <input type="text" name="fName">
<input type="submit">
</form>
The key is to have the correct action
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