for loop only executes once

Question

Here is my code. My outer loop only iterates once instead of ten times. I know this because System.out.println(i + " " + word) only happens once. I do not understand why.

edit: I've added my full method that this is included in. Part of a program to create a character array that makes a word search puzzle. rows = 23. cols = 11. Word[] is an array that includes starting row and col value for each word entered into the array, if the word will be horizontal or vertical, etc.

public static char[][] createPuzzle(int rows, int cols, Word[] words) {

    char[][] grid = new char[rows][cols];
    for (Word h : words) {
        System.out.println(h.getWord());
    }
    try{
        for(int i = 0; i<=9; i++){
            String word = words[i].getWord();
            System.out.println(i + " " + word);
            boolean hor = words[i].isHorizontal();
            if (hor == true){
                for(int j = 0; j <= word.length(); j++){
                    grid[words[i].getRow()][words[i].getCol()+j] = word.charAt(j);
                }
            } else if (hor == false){
                for(int k = 0; k <= word.length(); k++){
                    grid[words[i].getCol()][words[i].getRow()+k] = word.charAt(k);
                }
            } 
        }
    } catch (StringIndexOutOfBoundsException | ArrayIndexOutOfBoundsException e){
        //catches exception
    }
    return grid;
}

Answer 1

This is because you are using the following syntax:

} catch (StringIndexOutOfBoundsException | ArrayIndexOutOfBoundsException e){
        //catches exception
}

What happens:

1. Somethere in your code was thrown an exception StringIndexOutOfBoundsException or ArrayIndexOutOfBoundsException . The exception breaks your for loop.
2. catch block cathes the exception, and...
3. does nothing , just ignores is and goes on.

So, you should add at least something like this

e.printStackTrace()

at your catch block.

Never ignore exceptions!