slicing list of lists in Python

Question

I need to slice a list of lists in python.

A = [[1,2,3,4,5],[1,2,3,4,5],[1,2,3,4,5]]
idx = slice(0,4)
B = A[:][idx]

The code above isn't giving me the right output.

What I want is : [[1,2,3],[1,2,3],[1,2,3]]

Answer 1

Very rarely using slice objects is easier to read than employing a list comprehension, and this is not one of those cases.

>>> A = [[1,2,3,4,5],[1,2,3,4,5],[1,2,3,4,5]]
>>> [sublist[:3] for sublist in A]
[[1, 2, 3], [1, 2, 3], [1, 2, 3]]

This is very clear. For every sublist in A , give me the list of the first three elements.

Answer 2

With numpy it is very simple - you could just perform the slice:

In [1]: import numpy as np

In [2]: A = np.array([[1,2,3,4,5],[1,2,3,4,5],[1,2,3,4,5]])

In [3]: A[:,:3]
Out[3]: 
array([[1, 2, 3],
       [1, 2, 3],
       [1, 2, 3]])

You could, of course, transform numpy.array back to the list :

In [4]: A[:,:3].tolist()
Out[4]: [[1, 2, 3], [1, 2, 3], [1, 2, 3]]

Answer 3

A = [[1,2,3,4,5],[1,2,3,4,5],[1,2,3,4,5]]

print [a[:3] for a in A]

Using list comprehension

Answer 4

您可以使用列表推导式，例如： [x[0:i] for x in A]其中i是 1,2,3 等，具体取决于您需要多少元素。

Answer 5

Either:

>>> [a[slice(0,3)] for a in A]
[[1, 2, 3], [1, 2, 3], [1, 2, 3]]

Or:

>>> [list(filter(lambda x: x<=3, a)) for a in A]
[[1, 2, 3], [1, 2, 3], [1, 2, 3]]

Answer 6

I am new in programming and Python is my First Language. it's only 4 to 5 days only to start learning. I just learned about List and slicing and looking for some example I found your problem and try to solve it Kindly appreciate if my code is correct. Here is my code A = [[1,2,3,4,5],[1,2,3,4,5],[1,2,3,4,5]] print(A[0][0:3],A[1][0:3],A[1][0:3])