I have a dict like:
original_dict = {'two':'2','three':'3','one':'1','foo':'squirrel'}
And I wanted two be in this order:
ordered_dict = OrderedDict({'one':'1','two':'2','three':'3','foo':'squirrel'
})
but I don't get the same order, {'one':'1','two':'2','three':'3','foo':'squirrel'}
creates a dict by itself so it doesn't work as I spected
I saw in the documentation that the sorted method can be used
OrderedDict(sorted(d.items(), key=lambda t: len(t[0])))
But I don't know a function to return the order I want I tried
ordered_dict = OrderedDict(sorted(original_dict.items(),['one','two','three','foo']))
But that didn't work.
Note that the order I want can be quite arbitrary, like:
['three','foo','one','two',]
order=['one','two','three','foo']
ordered_dict = OrderedDict((k, original_dict[k]) for k in order)
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