I am implementing django application where I have two models file and filepage in which filepage model has a foreign key file.
currently my view looks like this:
Container P Bucket_type
f1 p1 doc1
f1 p2 doc2
f1 p3 doc3
f2 p4 doc4
f2 p5 doc5
I want to convert it into:
Container P Bucket_type
f1 p1,p2,p3 doc1,doc2,doc3
f2 p4,p5 doc4,doc5
the container name is field in my container model and student and bucket type are in bucket model.
Updated:
class Containers(models.Model):
name = models.CharField(max_length=30)
class Bucket(models.Model):
file = models.ForeignKey(Container, on_delete=models.CASCADE, related_name='buckets')
bucket_number = models.IntegerField()
p = models.ForeignKey(P, null=True, blank=True)
bucket_type = models.ForeignKey(D, null=True, blank=True)
currently I am trying to write a function which combines this records but it is taking time to make that list of combinations as I have bulk of records in my database.
Is there any way to create this data using Django's third party packages or any other solution?
Your Bucket
model should look like this
class Bucket(models.Model):
file = models.ForeignKey(Container, on_delete=models.CASCADE, related_name='buckets')
bucket_number = models.IntegerField()
student = models.ManyToManyField(Student, null=True, blank=True)
bucket_type = models.ManyToManyField(BucketType, null=True, blank=True)
You can Try to create Charfield or Charfields in YouModel:
patient1 = FilePage.objects.order_by('patient')[0] # -- [0] or other variant
document1 = FilePage.objects.order_by('document_type')[0] # -- [0] or other variant
YouModel.objects.order_by('charfield').update(charfield=patient1) # Something like this construction.
For Most convenient construction i need to Ask You "What You Want?", and comment You post. But i can t do this because i havn
t 50 REPUTATION.
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