What concrete type can accept an IEnumerable<T>

Question

i have a method with a return type of IEnumerable<T> , and I need to capture the output of this method in a variable. I cannot use var to declare the variable, because the variable has to be declared outside of my try/catch block. So, what concrete Type can I use to declare my variable, that will accept the IEnumerable<T> output of my method? Here's what this scenario looks like:

IEnumerable<string> CalleeMethod() {...}

IEnumerable<string> CallerMethod() 
{
   List<string> temp = null;
   try
   {
      temp = CalleeMethod();
   }
   catch(Exception exception)
   {
      Debug.WriteLine(exception.GetBaseException().Message);
   }
   return temp;
}

This example doesn't work because when I declare temp as List<T> , I get the error: cannot convert IEnumerable<T> to List<T> . I know I can call .ToList() , or cast the output of CalleeMethod() to List<T> , but I am wanting to simply define the temp variable with a concrete Type that can hold the IEnumerable<T> output of CalleeMethod() without having to cast it. So, what concrete Type can I declare temp as that will not throw the cannot convert... error?

Thanks in advance for any help!

Answer 1

您是否尝试过IEnumerable<String> ？

Answer 2

只需使用IEnumerable<string> temp = Enumerable.Empty<String>();

Answer 3

@hvd is correct. I think you have some concepts crossed. 'IEnumerable T' is different then 'IEnumerable string '. This is a simple generic version...

public class GenericTest
{
    public IEnumerable<T> CalleeMethod<T>() where T : class
    {
        return new List<T>();
    }
}
[TestMethod]
public void IEnumberableT()
{
    var x = new GenericTest();
    IEnumerable<string> result = x.CalleeMethod<string>();
}