How to call function that is being shadowed by another one earlier in the MATLAB search path?

Question

By way of preamble, consider this example from Unix. Suppose that /some/path/foo and /some/other/path/foo are both available executables. Also, suppose that both /some/path and /some/other/path are present in the $PATH environment variable, with /some/path appearing first. Then, if I run

% foo

the foo that gets run is /some/path/foo . That's what the $PATH variable is all about.

Nevertheless , I can always invoke the other foo by referring to it by its full path, like this:

% /some/other/path/foo

IOW, once I refer to the command by its full path, no name resolution needs to happen, so $PATH plays no role in deciding which foo gets run.

Importantly, this mechanism does not require modifiying the $PATH variable. One just sidesteps it.

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With this example in mind, does MATLAB provide a way (other than changing the search path) to run a function foo from a file different from the first candidate file in the MATLAB search path?

Answer 1

请参见MATLAB 函数句柄和feval 。