how can I concat more rationally first item of array to first of second array and so on? Basically automate console.log here is the code:
$("button#search").on("click", function(){
var inputVal = $("input#text").val();
$.getJSON("https://en.wikipedia.org/w/api.php?action=opensearch&search=" + inputVal +"&limit=5&namespace=0&format=json&callback=?", function(json) {
var itemName = $.each(json[1], function(i, val){
})
var itemDescription = $.each(json[2], function(i, val){
})
var itemLink = $.each(json[3], function(i, val){
})
console.log(itemName[0] + " " + itemDescription[0] + " " + itemLink[0]);
console.log(itemName[1] + " " + itemDescription[1] + " " + itemLink[1]);
console.log(itemName[2] + " " + itemDescription[2] + " " + itemLink[2]);
console.log(itemName[3] + " " + itemDescription[3] + " " + itemLink[3]);
console.log(itemName[4] + " " + itemDescription[4] + " " + itemLink[4]);
})//EOF getJSON
});//EOF button click
I believe this is what you are looking for:
for (var i = 0; i < itemName.length; i++) {
console.log(itemName[i] + " " + itemDescription[i] + " " + itemLink[i]);
}
If arrays have the same length, you could use map
var result = $.map(json[1], function(i, val){
var row = val + " " + json[2][i] + " " + json[3][i];
console.log(row);
return row;
}
Also you can use that result
later, eg
console.log(result[0]);
Using es6 you can do the following:
(in your getJson callback):
function (json) {
const [value, optionsJ, descriptionsJ, linksJ] = json;
let whatIwant = [];
// choose one to loop through since you know they will all be the same length:
optionsJ.forEach(function (option, index) {
whatIwant.push({option: option, description: descriptionJ[index], link: linksJ[index]});
});
// use whatIwant here**
}
Your new whatIwant
array will then contain objects for each set.
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