Why am I getting array how to get string

Question

If I have textarea with id leavepost and hidden div id display After # I got hidden div and word with # in var name But when I want to sent itvia ajax to sul file it sends array. What is wrong?

$("#leavepost").keypress(function(event) {
    var key = (event.keyCode ? event.keyCode : event.which);
    if (key == 35) {
        $('#display').show();
        $('#leavepost').on('keyup', function() {
            var name = $(this).val().match(/(^|\s)(#[a-z\d-]+)/ig);
            $.ajax({
                type: "POST",
                url: "d/sul.php",
                data: { su: name },
                success: function(sss)
                {
                    $('#display').html(sss);

                }
            });
        }).keyup();
    }
});

Inside sul.php I have:

echo $_POST['su'];
$u = mysqli_real_escape_string($con, $_POST['su']);

error:

Warning: mysqli_real_escape_string() expects parameter 2 to be string, array given

Answer 1

.match() returns an array of matching tests.

// for example:
"xzxzxz".match(/z/gi)    // => [z,z,z]
"xzxzxz".match(/z/gi)[0] // => "z"

Either use .match(/(^|\\s)(#[az\\d-]+)/ig)[0] to get the first match.

or you can .match(/(^|\\s)(#[az\\d-]+)/ig).join(",") to send all the test matches in a string.

// for example
"xzxzxz".match(/z/gi).join(",") // => "z,z,z"
"xzxzxz".match(/z/gi).join("")  // => "zzz"

Answer 2

You use in this code var name = $(this).val().match(/(^|\\s)(#[az\\d-]+)/ig); String.prototype.match() and this method return:

An Array containing the entire match result and any parentheses-captured matched results, or null if there were no matches.

So you need to work with $_POST['su']; variable in your php code as with array

Answer 3

It is because the JavaScript match function returns an array.

https://developer.mozilla.org/en/docs/Web/JavaScript/Reference/Global_Objects/String/match

You need to extract the name part from that array. console.log(name) will give you the structure of the array.